## draw the graph of 4x-3y +4=0 and 4x+3y -20=0 in the same x-y plane shade the region bounded by these lines and x axis.find the area of the s

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Answer:Express the volume of the solid under the plane 4x−2y+z=18 and above the region bounded by 4x+y=16 and x2+y=16.

Can’t determine lower y boundary!

Volume = ∫40∫16−x2018−4x+2ydydx

For some reason volume doesn’t start being integrated from y = 0.

Why?? It clearly should, judging by the quick sketch.

You basically need that red-shaded region (and then imagine there’s a plane above that red-shaded region).

So y definitely starts from 0… why not?

I mean, when x = 4, y = 0, no?

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